Преобразование mysql-запроса в объект JSON с использованием php?

Я пытаюсь преобразовать mySQL-запрос в объект JSON. Это работает:

<?php // load in mysql server configuration (connection string, user/pw, etc) include 'mysqlConfig.php'; $year = $_GET['year']; // connect to the database @mysql_select_db($dsn) or die( "Unable to select database"); // outputs the db as lines of text. $result = mysql_query("SELECT COUNTY, COUNT(TYPE) AS 'type' from data WHERE DATE between '2000-01-01' and '2000-12-31' GROUP BY COUNTY"); $rows = array(); while($r = mysql_fetch_assoc($result)) { $rows[] = $r; } echo json_encode($rows); mysql_close(); ?> 

Но я получаю этот вывод:

 [{"COUNTY":"Carlow","type":"121"},{"COUNTY":"Cavan","type":"130"},{"COUNTY":"Clare","type":"112"},{"COUNTY":"Cork","type":"833"},{"COUNTY":"Donegal","type":"264"},{"COUNTY":"Dublin","type":"2457"},{"COUNTY":"Galway","type":"287"},{"COUNTY":"Kerry","type":"227"},{"COUNTY":"Kildare","type":"300"},{"COUNTY":"Kilkenny","type":"139"},{"COUNTY":"Laois","type":"123"},{"COUNTY":"Leitrim","type":"39"},{"COUNTY":"Limerick","type":"370"},{"COUNTY":"Longford","type":"85"},{"COUNTY":"Louth","type":"257"},{"COUNTY":"Mayo","type":"231"},{"COUNTY":"Meath","type":"268"},{"COUNTY":"Monaghan","type":"136"},{"COUNTY":"Offaly","type":"97"},{"COUNTY":"Roscommon","type":"115"},{"COUNTY":"Sligo","type":"113"},{"COUNTY":"Tipperary","type":"249"},{"COUNTY":"Waterford","type":"205"},{"COUNTY":"Westmeath","type":"118"},{"COUNTY":"Wexford","type":"246"},{"COUNTY":"Wicklow","type":"235"}] 

тогда как это формат, который я ищу:

 {"Carlow":3,"Cavan":4,"Clare":5,"Cork":3,"Donegal":4,"Dublin":5,"Galway":4,"Kerry":5,"Kildare":5,"Kilkenny":12,"Laois":4,"Leitrim":4,"Limerick":4,"Longford":4,"Louth":4,"Mayo":5,"Meath":3,"Monaghan":5,"Offaly":4,"Roscommon":3,"Sligo":3,"Tipperary":4,"Waterford":2,"Westmeath":2,"Wexford":4,"Wicklow":2} 

Есть идеи?