Я импортирую CSV-файл в свою область администрирования, и я хочу добавить файлы в свою базу данных. Мой PHP-код для import.php :
<?php include_once('../include/connection.php'); if ($_FILES[csv][size] > 0) { //get the csv file $file = $_FILES[csv][tmp_name]; $handle = fopen($file,"r"); //loop through the csv file and insert into database do { if ($data[0]) { mysql_query("INSERT INTO mobi(promo_title, promo_content, promo_image, promo_link, promo_cat, promo_name) VALUES ( '".addslashes($data[0])."', '".addslashes($data[1])."', '".addslashes($data[2])."', '".addslashes($data[3])."', '".addslashes($data[4])."', '".addslashes($data[5])."' ) "); } } while ($data = fgetcsv($handle,1000,",","'")); // //redirect header('Location: import.php?success=1'); die; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Import a CSV File with PHP & MySQL</title> </head> <body> <?php if (!empty($_GET[success])) { echo "<b>Your file has been imported.</b><br><br>"; } //generic success notice ?> <form action="" method="post" enctype="multipart/form-data" name="form1" id="form1"> Choose your file: <br /> <input name="csv" type="file" id="csv" /> <input type="submit" name="Submit" value="Submit" /> </form> </body> </html>в<?php include_once('../include/connection.php'); if ($_FILES[csv][size] > 0) { //get the csv file $file = $_FILES[csv][tmp_name]; $handle = fopen($file,"r"); //loop through the csv file and insert into database do { if ($data[0]) { mysql_query("INSERT INTO mobi(promo_title, promo_content, promo_image, promo_link, promo_cat, promo_name) VALUES ( '".addslashes($data[0])."', '".addslashes($data[1])."', '".addslashes($data[2])."', '".addslashes($data[3])."', '".addslashes($data[4])."', '".addslashes($data[5])."' ) "); } } while ($data = fgetcsv($handle,1000,",","'")); // //redirect header('Location: import.php?success=1'); die; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Import a CSV File with PHP & MySQL</title> </head> <body> <?php if (!empty($_GET[success])) { echo "<b>Your file has been imported.</b><br><br>"; } //generic success notice ?> <form action="" method="post" enctype="multipart/form-data" name="form1" id="form1"> Choose your file: <br /> <input name="csv" type="file" id="csv" /> <input type="submit" name="Submit" value="Submit" /> </form> </body> </html>
Код отображается правильно, но когда я выбираю свой тестовый файл и нажимаю submit, я сталкиваюсь с этими проблемами:
Warning: mysql_query() [function.mysql-query]: Access denied for user 'root'@'localhost' (using password: NO) in admin/import.php on line 23 Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in admin/import.php on line 23 Warning: mysql_query() [function.mysql-query]: Access denied for user 'root'@'localhost' (using password: NO) in admin/import.php on line 23 Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in admin/import.php on line 23 Warning: mysql_query() [function.mysql-query]: Access denied for user 'root'@'localhost' (using password: NO) in admin/import.php on line 23 Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in admin/import.php on line 23 Warning: mysql_query() [function.mysql-query]: Access denied for user 'root'@'localhost' (using password: NO) in admin/import.php on line 23 Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in admin/import.php on line 23 Warning: Cannot modify header information - headers already sent by (output started at admin/import.php:1) in admin/import.php on line 29
Может ли кто-нибудь увидеть причину?
мой код connection.php:
<?php try { $pdo = new PDO('mysql:host=localhost;dbname=*********', '*********', '*********'); }catch (PDOException $e){ exit('Database Error.'); } ?>
обратите внимание, что мои другие страницы, такие как add.php, delete.php, edit.php и т. д., работают с одним и тем же include_once для connection.php
ТАК НИЧЕГО НЕ СМОТРЕТЬ С МОЕЙ ПОДКЛЮЧЕНИЕМ БАЗЫ ДАННЫХ.
Спасибо.